pqxx::exclusive_bound< TYPE > Class Template Reference

An exclusive boundary value to a pqxx::range. More...

#include <range.hxx>

Public Member Functions
	exclusive_bound ()=delete
constexpr	exclusive_bound (TYPE const &value)
constexpr TYPE const &	get () const &noexcept
constexpr bool	extends_down_to (TYPE const &value) const noexcept(noexcept(m_value< value))
	Would this bound, as a lower bound, include value? More...
constexpr bool	extends_up_to (TYPE const &value) const noexcept(noexcept(value< m_value))
	Would this bound, as an upper bound, include value? More...

Detailed Description

template<typename TYPE>
class pqxx::exclusive_bound< TYPE >

An exclusive boundary value to a pqxx::range.

Use this as a lower or upper bound for a range if the range should not include the value.

Constructor & Destructor Documentation

exclusive_bound() [1/2]

template<typename TYPE >

pqxx::exclusive_bound< TYPE >::exclusive_bound ( )

delete

exclusive_bound() [2/2]

template<typename TYPE >

constexpr pqxx::exclusive_bound< TYPE >::exclusive_bound ( TYPE const &  value )

explicitconstexpr

References pqxx::is_null().

Member Function Documentation

extends_down_to()

template<typename TYPE >

constexpr bool pqxx::exclusive_bound< TYPE >::extends_down_to ( TYPE const &  value ) const

constexprnoexcept

Would this bound, as a lower bound, include value?

extends_up_to()

template<typename TYPE >

constexpr bool pqxx::exclusive_bound< TYPE >::extends_up_to ( TYPE const &  value ) const

constexprnoexcept

Would this bound, as an upper bound, include value?

get()

template<typename TYPE >

constexpr TYPE const& pqxx::exclusive_bound< TYPE >::get ( ) const &

constexprnoexcept

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The documentation for this class was generated from the following file:

• range.hxx